o rind the probability of a z-score, position the orange line at the appropriate
ID: 3375869 • Letter: O
Question
o rind the probability of a z-score, position the orange line at the appropriate z-score on the horizontal axis. The areas under the standard normal curve to the left and right of the vertical line are displayed in blue and orange, respectively. (Hint: The standard normal distribution is symmetrical about the mean, the area under the curve to the left (and right) of the mean is 0.5. Therefore, the area that corresponds with Mean to z is computed as Larger Portion (Body or Tail) - 0.5.) Standard Normal Distribution Mean-0.0 Standard Deviation 1.0 5000 000 3.00 2.50 -2.00 1.50 1.00 0.50 0.00 0.50 1.00 1.50 2.00 2.50 3.00 0.000Explanation / Answer
from above:
z body tail mean to z z body tail mean to z 0.25 0.5987 0.4013 0.0987 1.55 0.9394 0.0606 0.4394 0.75 0.7734 0.2266 0.2734 2.15 0.9842 0.0158 0.4842 1.1 0.8643 0.1357 0.3643 2.65 0.9960 0.0040 0.4960 1.3 0.9032 0.0968 0.4032 2.8 0.9974 0.0026 0.4974Related Questions
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