The following frequency distribution shows the days absent taken during a calend

ID: 3376003 • Letter: T

Question

The following frequency distribution shows the days absent taken during a calendar year by employees of a manufacturing company; Days Absent Number of Employees 1 - 5 47 6 - 10 17 11 - 15 13 16 - 20 8 21 - 25 3 How many employees were absent at least 11 days? ANSWER: What percent of the employees were absent less than 16 days? Report your final answer to 2 decimal places, using conventional rounding rules. ANSWER: % What is the relative frequency for the fourth class interval from “16 - 20”? Report your final answer to 2 decimal places, using conventional rounding rules. ANSWER: What is the midpoint for the class interval with the smallest frequency? Report your final answer to 2 decimal places, using conventional rounding rules. ANSWER: What is the approximate mean number of days absent? Report your final answer to 2 decimal places, using conventional rounding rules. ANSWER:

Explanation / Answer

Solution

Preparatory Work

Given frequency distribution alongwith related working

Class #

(i)

Class Limits

Mid-point

(xi)

Frequency

(fi)

Relative Frequency

Cumulative Frequency (CF)

xi.fi

1 – 5

141

6 – 10

136

11 – 15

169

16 – 20

8/88 = 0.09

144

21 - 25

Total

659

Number of employees absent for at least 11 days = 88 – CF of 2nd class = 24 ANSWER 1

Percentage of employees absent for less than 16 days = 100 x (CF of 3rd class)/88

= (100 x 77)/88 = 87.5% ANSWER 2

Relative frequency of fourth class = 0.0909 or 9.09% ANSWER 3

Mid-point of the class with the smallest frequency = x5 = 23 ANSWER 4

Mean = [?(i = 1, 5){(xi.fi)}]/ [?(i = 1, 5)(fi)] = 659/88 = 7.4885 ANSWER 5

DONE