The frequency distribution below shows the distribution for checkout time (in mi

Question

The frequency distribution below shows the distribution for checkout time (in minutes) in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon.

2. Complete the frequency table with frequency and relative frequency. Express the relative

frequency to two decimal places.

What percentage of the checkout times was at least 3 minutes?

In what class interval must the median lie? Explain your answer.

Does this distribution have positive skew or negative skew? Why?

(5 pts) (3 pts)

(5 pts) (2 pts)

Checkout Times(In minutes) Frequency Relative Frequency 1.0-1.9 3 2.0-2.9 12 3.0-3.9 0.20 4.0-4.9 3 5.0-5.9 Total 25

Explanation / Answer

Relative frequency for 1-1.9 = 3/25 = 0.12

Frequency for 3 - 3.9= 25*0.2 = 5

For 5 - 5.9 is the total 25 - frequ of other rows

Similarly prob = 1- total of others

As cum frequency is 0.5 in 2-2.9, median lies here

This implies that this is right skewed

Checkout Times(In minutes) Frequency Relative Frequency 1.0-1.9 3 0.12 2.0-2.9 12 0.48 3.0-3.9 5 0.2 4.0-4.9 3 0.12 5.0-5.9 2 0.08 Total 25 1

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