This question meant to help with the notion of condilinal probabiy anid rando va
ID: 3383142 • Letter: T
Question
Explanation / Answer
P(X2 =0) = (Both cases when (X1=0 , X2=0) and (X1=1,X2=0) )
=(1/2 * 0.6) + (1/2 * 1/2)
= 0.55
P(X1=1 / X2 =0) = P( X1 = 1 AND X2 = 0) / P (X2 = 0)
= ( 1/2 * 0.6 ) / 0.55
= 0.5455 Answer
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