A market analyst wants to know if the new website he designed is showing increas

Question

A market analyst wants to know if the new website he designed is showing increased page views per visit. A customer is randomly sent to one of two different websites. offering the same products, but with different designs. The accompanying table shows the data from five randomly chosen customers from each website Assume that the data come from a distribution that is Normally distributed. Complete pans a through c below. Click the icon to view the data table of website page views per visit a) Find a 95% confidence interval for the mean difference, Mu1 - Mu2, in page views from the two websites (Round to two decimal places as needed.)

Explanation / Answer

CI = x1 - x2 ± t a/2 * Sqrt ( sd1 ^2 / n1 + sd2 ^2 /n2 )
Where,
x1 = Mean of Sample 1, x2 = Mean of sample2
sd1 = SD of Sample 1, sd2 = SD of sample2
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval
Mean(x1)=8.6
Standard deviation( sd1 )=4.4497
Sample Size(n1)=5
Mean(x2)=8.2
Standard deviation( sd2 )=55.4497
Sample Size(n1)=5
CI = [ ( 8.6-8.2) ±t a/2 * Sqrt( 19.79983009/5+3074.66923009/5)]
= [ (0.4) ± t a/2 * Sqrt( 618.89) ]
= [ (0.4) ± 2.776 * Sqrt( 618.89) ]
= [-68.66 , 69.46]

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