Weights (kg) of poplar trees were obtained from trees planted in a sandy and dry
ID: 3384949 • Letter: W
Question
Weights (kg) of poplar trees were obtained from trees planted in a sandy and dry region. The trees were given different treatments identified in the table below. The data are from a study conducted by researchers at Pennsylvania State University and were provided by Minitab, Inc. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective in the sandy and dry region? Use analysis of variance for the indicated test.
No Treatment
Fertilizer
Irrigation
Fertilizer and Irrigation
0.24
0.92
0.96
1.07
1.69
0.07
1.43
1.63
1.23
0.56
1.26
1.39
0.99
1.74
1.57
0.49
1.80
1.13
0.72
0.95
Multiple Choice
a.)Test statistic : F= 0.3801, P value: 0.769, fail to reject Ho : U1=U2=U3=U4
b.)Test Statistic : F = 8.7254, P value : 0.00037, reject Ho: U1=U2=U3=U4
c.)Test Statistic : F= 0.3801, P value 0.16, fail to reject Ho: U1 =U2=U3=U4
d.)Test Statistic : F= 8.7254, P value : 0.4722, fail to reject Ho: U1= U2=U3=U4
e.)Test Statistic : F = 5. 2878, P Value : 0.0061, reject Ho: U1= U2=U3=U4
No Treatment
Fertilizer
Irrigation
Fertilizer and Irrigation
0.24
0.92
0.96
1.07
1.69
0.07
1.43
1.63
1.23
0.56
1.26
1.39
0.99
1.74
1.57
0.49
1.80
1.13
0.72
0.95
Explanation / Answer
Sol)
Hence from above excel output
a.)Test statistic : F= 0.3801, P value: 0.769,
Hence p value > 0.05 , we fail to reject Ho :
H0:U1=U2=U3=U4
Anova: Single Factor SUMMARY Groups Count Sum Average Variance No Treatment 5 5.95 1.19 0.39155 Fertilizer 5 4.42 0.884 0.39053 Irrigation 5 5.94 1.188 0.12017 Fertilizer and Irrigation 5 5.53 1.106 0.19008 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 0.3114 3 0.1038 0.380105 0.768664 3.238872 Within Groups 4.36932 16 0.273083 Total 4.68072 19Related Questions
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