A professional employee in a large corporation receives an average or mu = 38.9
ID: 3392865 • Letter: A
Question
A professional employee in a large corporation receives an average or mu = 38.9 e-mans per day. Most of these e-mails are from other employees in the company. Because of the large number of e-mails, employees find themselves distracted and are unable to concentrate when they return to their tasks. In an effort to reduce distraction caused by such interruptions, one company established a priority list that all employees were to use before sending an e-mail. One month after the new priority list was put into place, a random sample of 31 employees showed that they were receiving an average of x = 30.1 e-mails per day. The computer server through which the e-mails are routed showed that alpha = 19.4. Has the new policy had any effect? Use a 10% level of significance to test the claim that there has been a change (either way) in the average number of e-mails received per day per employee. Are the data statistically significant at level alpha? Based on your answers, will you reject or fail to reject the null hypothesis?Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u = 38.9
Ha: u =/ 38.9
As we can see, this is a two tailed test.
Thus, getting the critical z, as alpha = 0.1 ,
alpha/2 = 0.05
zcrit = +/- 1.644853627
Getting the test statistic, as
X = sample mean = 30.1
uo = hypothesized mean = 38.9
n = sample size = 31
s = standard deviation = 19.4
Thus, z = (X - uo) * sqrt(n) / s = -2.525583835
Also, the p value is
p = 0.011550622
As P < 0.10, we reject Ho.
Thus,
OPTION A: The P value is less than the level of significance so the data are statistically significant. [ANSWER, A]
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