According to a recent poll 53% of Americans would vote for the incumbent preside

Question

According to a recent poll 53% of Americans would vote for the incumbent president If a random sample of 200 people results in 45% who would vote for the incumbent, test the claim that the actual percentage is 53%. Use a 0.10 significance level Ho: H1: CV: TS: P-value: Reject Ho? Conclusion: The health of employee* is monitored by periodically weighing them in. A sample of 34 employees has a mean weight of 183.9 lb. and a standard deviation of 21.2 lb. use a 0.10 significant level to test the claim that the population mean of all such employees weights is less than 200 lb. Hi: H1: CV: TS: P-value: Reject Ho? Conclusion:

Explanation / Answer

1.

Formulating the null and alternatuve hypotheses,          
          
Ho:   p   =   0.53
Ha:   p   =/=   0.53
As we see, the hypothesized po =   0.53      
Getting the point estimate of p, p^,          
          
p^ = x / n =    0.45      
          
Getting the standard error of p^, sp,          
          
sp = sqrt[po (1 - po)/n] =    0.035291642      
          
Getting the z statistic,          
          
z = (p^ - po)/sp =    -2.266825665      
          
As this is a    2   tailed test, then, getting the p value,  
          
p =    0.023400878      
significance level =    0.1      

As P < 0.1, we   REJECT THE NULL HYPOTHESIS.      

Thus, there is significant evidence that the actual percentage is not 53%. [CONCLUSION]

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