A survey of 1,692 randomly selected adults showed that 503 of them have heard of

ID: 3393938 • Letter: A

Question

A survey of 1,692 randomly selected adults showed that 503 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 33% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).

Sample proportion:

0.297281

Test statistic,

z: 2.8622

Critical z:

±1.96001.9600

P-Value:

0.0042

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis.

A. : H0: p0.33

B. H0: p=0.33

C. H0: p<0.33

D. H0: p>0.33

Choose the correct answer below.

A. Reject the null hypothesis because the P-value is less than or equal to the significance level,.

B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, .

C. Reject the null hypothesis because the P-value is greater than the significance level, .

D. Fail to reject the null hypothesis because the P-value is greater than the significance level, .

e. What is the final conclusion?

A.There is sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

B. There is not sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

C. There is sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.

D.There is not sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.