Water and Carbohydrates. Continuing on the theme of fruits and vegetables, here
ID: 3394175 • Letter: W
Question
Water and Carbohydrates. Continuing on the theme of fruits and vegetables, here are the number of grams of water and the number of grams of carbohydrates for a random selection of raw foods (100 g each). Is there a linear relationship between the variables? Find the critical value (from table 1) (example: .123) Compute the test value using the formula or calculator (round to three decimal places, example .645): Reject the null or do not reject the null (type in either Reject the null or do not reject the null only): Conclusion sentence (type in either is or is not only, to reflect what you found) and state if it is positive or negative. There enough evidence to support a relationship Find the equation of the regression line y' = a + bx and fill in a and b below (round a and b to three decimal places, example: 4.123 or .234) If there are 75 grams of water, how many grams of carbs? (do not round)Explanation / Answer
1. Ho : rho=0 VS H1: rho does not equal to 0
The calculated rho value is -0.9926842.
2. Critical value of t-distribution for 5% level of significance with 6 degree of freedom is 2.4469.
3. Computation of test statistic
t={rho(sqrt(n-2))}/{sqrt(1-rho^2}={-.9927*sqrt(7-2)}/{sqrt(1-(-0.9927)^2)}= --18.3843
4. Reject the null hypothesis and Accept the alternative hypothesis.
5. Conclusion. Since calculated | t | is greater than critical t value (2.4469), H1 accepted strongly at 5% level of significance and we may conclude that the water and carbonhydrate contain in the theme of fruits and vegitable is significantly negative correlation.
6 The linera regression model is
y= 87.408+(- 0.868)x
8. y=87.408+(- 0.868)*75
y=22.31
The carbohydrate value at 75gm of water is 22.31 gm.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.