Which of the following is correct? The mean square error is an estimate of the w
ID: 3395035 • Letter: W
Question
Which of the following is correct?
The mean square error is an estimate of the within group standard error.
About 95% of individuals in the control group had a change in bone density between about 580 and 620.
Based on the overlap of the confidence intervals, there is little evidence to separate the means of the low impact group and the control group.
The sample standard deviations are too unequal, so the results of the ANOVA cannot be trusted.
Which of the following is correct?
The mean square error is an estimate of the within group standard error.
About 95% of individuals in the control group had a change in bone density between about 580 and 620.
Based on the overlap of the confidence intervals, there is little evidence to separate the means of the low impact group and the control group.
The sample standard deviations are too unequal, so the results of the ANOVA cannot be trusted.
Means and Std Deviations Std Err Level Control Highjump Lowjump Number Mean Std Dev Mean Lower 95% Upper 95% 10 601.100 27.3636 8.653 581.53 620.6 10 638.700 16.5935 5.2473 626.83 650.57 10 612.500 19.3290 6.1124598.67626.3.3 Analysis of Variance Sum of DF Squares Mean Square FRatio Prob>F Source Group Error C. Total 2 7433.867 3716.93 7.9778 0.0019* 465.91 27 12579.500 29 20013.367Explanation / Answer
The mean square error is an estimate of the within group standard error. TRUE.
About 95% of individuals in the control group had a change in bone density between about 580 and 620. FALSE.
Based on the overlap of the confidence intervals, there is little evidence to separate the means of the low impact group and the control group.TRUE.
The sample standard deviations are too unequal, so the results of the ANOVA cannot be trusted. TRUE
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