Use the following information to calculate your answers to questions 1 through 1

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Use the following information to calculate your answers to questions 1 through 12.

The table below shows the results of a study on smoking and three illnesses. We are interested in determining if the proportions of smokers in the three categories are different from each other.

p1 = proportions of smokers with emphysema

p2 = proportions of smokers with heart problem

p3 = proportions of smokers with cancer

Question 1

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Which of the following represents the null and alternative hypotheses in this case?

Select one:

a. Ho: p1 = p2 = p3                              Ha: Not all population proportions are equal

b. Ho: p1 = p3                                      Ha: p3 = p2

c. Ho: p1 = p2                                      Ha: p2 = p3

d. Ho: p1 = p2 = p3 = ptotal                 Ha: Not all population proportions are equal

Question 2

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The expected frequency of non-smokers with heart problem is

Select one:

a. 318

b. 96

c. 212

d. 144

e. 0.60

Question 3

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The expected frequency of smokers with cancer is

Select one:

a. 96

b. 212

c. 144

d. 0.40

e. 318

Question 4

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The expected frequency of non-smokers with emphysema is

Select one:

a. 318

b. 123

c. 96

d. 82

e. 0.40

Question 5

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The expected frequency of smokers with emphysema is

Select one:

a. 82

b. 0.40

c. 96

d. 212

e. 123

Question 6

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The chi-square value is

Select one:

a. 27.12

b. 1.52

c. 12.66

d. 1.01

e. 5.90

Question 7

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With = 0.1, the critical X2 value is

Select one:

a. 10.645

b. 4.605

c. 6.251

d. 2.706

e. 9.236

Question 8

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The conclusion is

Select one:

a. reject Ho since X2 is less than critical X2.

b. accept Ho since X2 is greater than critical X2.

c. No conclusion can be drawn.

d. reject Ho since X2 is greater than critical X2.

e. accept Ho since X2 is less than critical X2.

Question 9

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P1 – P2 is

Select one:

a. 0.14

b. 0.097

c. 0.12

d. 5

e. –21

Question 10

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P2 – P3 is

Select one:

a. 0.097

b. 0.017

c. 5

d. 0.082

e. 0.14

Question 11

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CV23 is

Select one:

a. 0.017

b. 0.097

c. 5

d. 0.082

e. 0.14

Question 12

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Using = 0.1, the conclusion of the pairwise comparison is

Select one:

a. emphysema vs heart problem & heart problem vs cancer are significant.

b. emphysema vs cancer & heart problem vs cancer are significant.

c. All pairwise comparisons are significant.

d. emphysema vs heart problem & emphysema vs cancer are significant.

e. None of the comparisons are significant.

Emphysema Heart Problem Cancer Total Smoker 145 140 300 585 Non-smoker 60 100 230 390 Total 205 240 530 975

Explanation / Answer

a. Ho: p1 = p2 = p3                              Ha: Not all population proportions are equal

b)

240*390 / 975 = 96

b. 96

c)

The expected frequency of smokers with cancer is

530 *585 / 975 = 318

The expected frequency of non-smokers with emphysema is

390*205 / 975 = 82

The expected frequency of smokers with emphysema is

585*205 / 975 = 123

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