Find the area of triangle ABC with the given parts. Round to the nearest tenth w

Question

Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary. 8) b = 15.4 ft A = 32degree30' C= 107degree10' A) 89.1 ft^2 B) 193.2 ft^2 C) 94.1 ft^2 10) A = 23degree40' b = 15.4 m c = 9.3 m A) 14.4 m^2 B) 57.4m^2 C) 59.4 m^2 D) 28.7 m^2 Find the angle between the pair of vectors to the nearest tenth of a degree. Find the indicated vector. 12) Let a = 3i, b = i + j. Find 6a - b. A) 17i - j B) 11i + j C) i - 17j D) 17i - 6j Find the component form of the indicated vector. 13) Let u = 6,4, v = 7, -8. Find 9u + 2v. A) 117,-8 B) 40,52 C) 90,-2 D) 68,20 14) Let u = -2,3, v = -6,4. Find 4u + 5v. A) 22,-8 B) -32,28 C) -38, 32 D) -38, 7 Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropriate. 15) a =27 ft b = 39 ft c = 43 ft A) No triangle satisfies the given conditions. B) A = 38.1degree, B = 62.9degree, C = 79degree C) A = 62.9degree, B = 38.1degree, C = 79degree D) A = 38.1degree, B = 31.5degree, C = 110.4degree

Explanation / Answer

8)A=32o30'=32.5o

C=107o10'=107.17o

A+B+C =180o

B=180o-32o30'-107o10'

B=180o-32o30'-107o10'

B=40o20'=40.33o

a/sinA=b/sinB

a/sin32.5o=15.4/sin40.33o

a=15.4sin32.5o/sin40.33o

a=12.785

area of triangle=(1/2)ab sinC

area of triangle=(1/2)(12.785*15.4)sin107o10'

area of triangle=94.06

area of triangle =94.1ft2

10)area =(1/2)bcsinA

area =(1/2)*15.4*9.3*sin(23040')

area =28.7 m2

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