A dietitian is planning a meal of beef, rice, and carrots for a patient. The pat
ID: 3410894 • Letter: A
Question
A dietitian is planning a meal of beef, rice, and carrots for a patient. The patient needs the meal to contain 81.8 grams of carbohydrate, 20.2 grams of protein and 7.2 grams of fat. The table below shows the number of grams of carbohydrate, protein, and fat in 100 grams of each food. (Note, the total is not 100 grams due to the water and fiber content of the food.) How much of each food should be used so that the patient gets the needed nutrients?
Carbs Protein Fat Beef 1 22 12 Rice 25 2 0 Carrots 8 1 0
Explanation / Answer
Here we are given
Carbohydrate Protein Fat
beef 1C 22P 12F
Rice 25C 2P 0F
carrots 8C 1P 0F
C >= 81.8
P >= 20.2
F >= 7.2
C = a + 25b + 8c
P = 22a + 2b + c
F = 12a + 0b+0c
we will apply Matrix to solve for a,b and c
Find the pivot in the 1st column in the 1st row
Multiply the 1st row by 22
Subtract the 1st row from the 2nd row and restore it
Multiply the 1st row by 12
Subtract the 1st row from the 3rd row and restore it
Make the pivot in the 2nd column by dividing the 2nd row by -548
Multiply the 2nd row by 25
Subtract the 2nd row from the 1st row and restore it
Multiply the 2nd row by -300
Subtract the 2nd row from the 3rd row and restore it
Make the pivot in the 3rd column by dividing the 3rd row by -0.19708029197079213
Multiply the 3rd row by 0.016423357664232974
Subtract the 3rd row from the 1st row and restore it
Multiply the 3rd row by 0.3193430656934307
Subtract the 3rd row from the 2nd row and restore it
Solution set:
a = 0.6000000000000176
b = 2.80000000000011
c = 1.399999999999654
X1 X2 X3 b 1 1 25 8 81.8 2 22 2 1 20.2 3 12 0 0 7.2Related Questions
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