When a car skids to a stop, the length L, in feet, of the skid marks is related

Question

When a car skids to a stop, the length L, in feet, of the skid marks is related to the speed, S, in miles per hour (mph), of the car by the function L = S62/30 h. In this formula, h is a constant that depends on the road surface (the friction coefficient). For dry concrete pavement, the value of h is about 0.85. According to this formula, what is the effect of doubling your speed on the stopping distance? Stopping distance is four times as great. Stopping distance doubles. Stopping distance is cut in half. Not enough information given.

Explanation / Answer

Given that

Stopping distance = L feet

Speed = S miles per hour

h = 0.85

L = S2 / 30h

If the speed is double then S = 2S

L = (2S)2 / 30h

L = 4S2 / 30h

L = 4 x ( S2 / 30h)

Hence,

if speed is double then stopping distance is four times as great

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.