I need help on the last question point (2,-2) ). An object moving in a straight

Question

I need help on the last question

point (2,-2) ). An object moving in a straight line at constant velocity has its equation of motion given by: s = so + zot, where s is the position at time t, so is the initial position, and y is the constant speed. a). What are the slope and y-intercept for this linear model? b). An object is moving at 10 ft/s. At time 5 seconds the object is at position s -60 feet What is the initial position so? ). A manufacturing firm buys a new machine for $150,000. After the machine is fully depre- ciated, it will have a salvage value of $5,000. Assuming a 15-year straight-line depreciation model, what will be the value of the machine after 10 years?

Explanation / Answer

Straight line depreciation

When t = 0, y = 150000
When t = 15, y = 5000

So, slope = (5000 - 150000) / (15 - 0)

Slope = -29000/3

So, the equation is of the form

y = (-29000/3)t + C

Clearly, the y-intercept is 150000

So, y = (-29000/3)t + 150000

When t = 10,
y = (-29000/3) * 10 + 150000
y = 53333.33

So, after 10 years,
the value is :

53333.33 dollars ------> ANSWER

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