Jamison Kovach Supply Company manufactures paper clips and other office products

Question

Jamison Kovach Supply Company manufactures paper clips and other office products. Although inexpensive, paper clips have provided the firm with a high margin of profitability. Sample size is 50. Results are given for the last 10 samples Sample123 Defectives4 567910 12 The type of control chart that is best to monitor this process is a) Establish the control limits to include 99.73% of the random variation in defectives. ucL (enter your response as a number between O and 1, rounded to three decimal places LCLp(enter your response as a number between O and 1, rounded to three decimal places) b) Has the process been in control Based on the developed control limits, the number of defectives has been c) If the sample size were 25 instead, how would your limits and conclusions change? ucLp·[ ](enter your response as ar mber between 0 and 1,rourded to tree decimal places). LCL,- (enter your response as a number between O and 1 rounded to three decinal places Based on the developed control limits, the number of defectives has been

Explanation / Answer

The type of control chart that is best to monitor this process is p-chart

a. UCLp and LCLp calculation:

b. The process is not in control as some defect rates are beyond upper control limit (UCLp)

Based on the developed control limits, the number of defectives has been one (sample 10)

c. If sample size is 25

Again the process is not in control as some defect rates are beyond the upper control limit (UCLp)

Based on the developed control limits, the number of defectives has been one (sample 10)

Sample Defectives Sample size Defect rate (Defectives/Sample size) 1 4 50 0.080 2 7 50 0.140 3 2 50 0.040 4 5 50 0.100 5 6 50 0.120 6 6 50 0.120 7 5 50 0.100 8 4 50 0.080 9 1 50 0.020 10 12 50 0.240 Total 52 500 P bar = (total Number of defectives/ total sample) 0.1040 Sp = (sqrt (P bar*(1- p bar)/sample size) 0.0432 z (at 99.73%) 3.00 UCL = (p bar + z x Sp) 0.2335 LCL = (p bar - z x Sp) -0.0255 p-bar 0.1040 Standard Deviation 0.0432 Z 3.00 UCLp 0.2335 LCLp 0.0000 If the value of LCL is negative then its taken as zero

Related Questions

Navigate

• Browse (All)
• Browse J
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.