6. Find critical value t0:025;13 and t0:995;5 for student t-distribution. 7. Giv
ID: 3429427 • Letter: 6
Question
6. Find critical value t0:025;13 and t0:995;5 for student t-distribution.
7. Given a random sample of size n = 25 from standard normal population,
nd value k such that P(??2:069 < T < k) = 0:965, where T is the sum of all
samples.
8.Consider
ipping one fair six-sided die, so that S = f1; 2; 3; 4; 5; 6g, and
P(s) = 1
6 for all s 2 S. Let X be the number showing on the die, so that
X(s) = s for s 2 S, Let Y = X2. Compute the cumulative distribution func-
tion FY (y) = P(Y y), for all possible values of y.
9. Let X Exponential(), Let Y = X3, compute the density fy of Y.
10. Given an example of a random variable X such that E(min(X; 100)) =
E(X)=2
Explanation / Answer
one tailed t0.025, 13 = 2.1604
t0.995,5 one tailed = 2.5706
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7) P(-2.069<T<k) =0.965 T is the sum of samples of size 25
Hence Mean x bar = T/25
P(-0.08<z<0.04k) = 0.965 =0.0319+0.0.9331
From z table we find that 0.04k = 1.50since 09331 = (0.4331+0.5) and z corresponding to 0.4331 is 1.5
k = 37.50
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8) Y = x2
Y takes values as 1,4,9,16,25,36
p = 1/6 each,.
Cumulative prob function for y = x2 is given below
1 1/6 4 1/3 9 1/2 16 2/3 25 5/6 36 1Related Questions
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