www.mathal.com/Student/playerTest asprNestld-91939139&centerwinnyes8fromplayeche

ID: 3431810 • Letter: W

Question

www.mathal.com/Student/playerTest asprNestld-91939139&centerwinnyes8fromplayecheckeyes; Heather Rhea 3/5/15 6:10 This Test: 116 pts In a study of 420062 cel 33 of 50 complete cancer at a rate that is phone users, 138 subiects developed brain cancer. Test the claim that cell phone users develop brain importance, use a different from the rate of0,0340% for people who do not use cel phones. Because this issue has such great 0.005 significance level Use this information to answer the folowing questions. a. Which of the following is the hypothesis test to be conducted? OA Hot p 0.00034 OB. He 0.00034 Hi p 0.00034 H1 p 0.00034 Oc Hop 0.00034 OO, Hop 0.00034 Hip 0.00034 H1 p 0.00034 OE. Ho p

Explanation / Answer

a).. C

b).. z = -0.40

c).. P= 0.6866

d).. A. there is not sufficient evidence

e).. B. The study does not suggest that a cell phone user is at a higher risk for brain cancer than a non cell phone user.

Z Test of Hypothesis for the Proportion

Data

Null Hypothesis P=

0.00034

Level of Significance

0.005

Number of Items of Interest

138

Sample Size

420062

Intermediate Calculations

Sample Proportion=p=138/420062=

0.000328523

Standard Error =sqrt(P*(1-P)/n)=

0.0000284

Z Test Statistic=(0.000385-0.00034)/0.0000284=

-0.4035

Two-Tail Test

Lower Critical Value

-2.8070

Upper Critical Value

2.8070

p-Value

0.6866

Do not reject the null hypothesis