mixed probability distributions 5.157 The grade-point averages of a large popula
ID: 3434194 • Letter: M
Question
mixed probability distributions
Explanation / Answer
(A) P(X>3) = P((X-mean)/s >(3-2.4)/0.5)
=P(Z>1.2) =0.1151 (from standard normal table)
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(b) P(X<1.9) = P(Z<(1.9-2.4)/0.5) = P(Z<-1) = 0.1587 (from standard normal table)
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(c) The probability is 0.1151^3 =0.001524846
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