Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

2) Find the critical t-values for the following hypothesis tests: a) two-tailed

ID: 3436940 • Letter: 2

Question

2) Find the critical t-values for the following hypothesis tests:
a) two-tailed test, level of Significance = .01, df = 14 _____________
b) one-tailed test, lower tail critical, level of significance = .05, df = 20 ____________
c) one-tailed test, upper tail critical, level of significance = .01, df = 7 ______________
d) two-tailed test, level of Significance = .05, df = 18 ____________
e) two-tailed test, level of Significance = .001, df = 39 ____________
3) It's well established, we'll assume, that lab rats require an average of 32 trials in a complex water maze before reaching a learning criterion of three consecutive errorless trials. To determine whether a mildly adverse stimulus has any effect on performance, a sample of seven lab rats were given a mild electrical shock just before each trial.
a) Given that X-Bar (the Mean of X) = 34.91 and s = 3.02, test the null hypothesis with t, using the .01 level of significance.
b) Construct a 99 percent confidence interval for the true number of trials required to learn the water maze
c) Interpret this confidence interval 2) Find the critical t-values for the following hypothesis tests:
a) two-tailed test, level of Significance = .01, df = 14 _____________
b) one-tailed test, lower tail critical, level of significance = .05, df = 20 ____________
c) one-tailed test, upper tail critical, level of significance = .01, df = 7 ______________
d) two-tailed test, level of Significance = .05, df = 18 ____________
e) two-tailed test, level of Significance = .001, df = 39 ____________
3) It's well established, we'll assume, that lab rats require an average of 32 trials in a complex water maze before reaching a learning criterion of three consecutive errorless trials. To determine whether a mildly adverse stimulus has any effect on performance, a sample of seven lab rats were given a mild electrical shock just before each trial.
a) Given that X-Bar (the Mean of X) = 34.91 and s = 3.02, test the null hypothesis with t, using the .01 level of significance.
b) Construct a 99 percent confidence interval for the true number of trials required to learn the water maze
c) Interpret this confidence interval 2) Find the critical t-values for the following hypothesis tests:
a) two-tailed test, level of Significance = .01, df = 14 _____________
b) one-tailed test, lower tail critical, level of significance = .05, df = 20 ____________
c) one-tailed test, upper tail critical, level of significance = .01, df = 7 ______________
d) two-tailed test, level of Significance = .05, df = 18 ____________
e) two-tailed test, level of Significance = .001, df = 39 ____________
3) It's well established, we'll assume, that lab rats require an average of 32 trials in a complex water maze before reaching a learning criterion of three consecutive errorless trials. To determine whether a mildly adverse stimulus has any effect on performance, a sample of seven lab rats were given a mild electrical shock just before each trial.
a) Given that X-Bar (the Mean of X) = 34.91 and s = 3.02, test the null hypothesis with t, using the .01 level of significance.
b) Construct a 99 percent confidence interval for the true number of trials required to learn the water maze
c) Interpret this confidence interval

Explanation / Answer

2) Find the critical t-values for the following hypothesis tests:

a) two-tailed test, level of Significance = .01, df = 14 ____2.9768_____

b) one-tailed test, lower tail critical, level of significance = .05, df = 20 __1.7247__

c) one-tailed test, upper tail critical, level of significance = .01, df = 7 ___2.998___

d) two-tailed test, level of Significance = .05, df = 18 ___2.1009___

e) two-tailed test, level of Significance = .001, df = 39 ____3.5581__

3)

a)

This is a 2-tailed t-test ....

Ho: mean = 32
Ha: mean 32

t-statistic = (34.91 - 32) / (3.02 / sqrt 7) = 2.55

P-value = 2P(t > 2.55) = 2(1-0.9946) = 0.0108

Since the P-value < 0.05, REJECT the null hypothesis.

(b)

Construct a 99 percent confidence interval for the true number of trials required to learn the water maze

CI = 34.91 ± (2.575)(3.02 / sqrt 7)

CI = (31.97, 37.85)

(c)

Interpret this confidence interval :

Since 32 is included in the interval (31.97, 37.85)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote