The calculations for a factorial experiment involving four levels of factor A, t

Question

The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST = 299, SSA = 23, SSB = 24, SSAB = 195.

Set up the ANOVA table and test for significance using = .05. Show entries to 2 decimals, if necessary.

The p-value for Factor A is

What is your conclusion with respect to Factor A?

The p-value for Factor B is

What is your conclusion with respect to Factor B?

The p-value for the interaction of factors A and B is

What is your conclusion with respect to the interaction of Factors A and B?

Source of Variation Sum of Squares Degrees of Freedom Mean Square F Factor A Factor B Interaction Error Total

Explanation / Answer

Interaction

The p-value of factor A with degree of freedom is (3,24) is 0.100

The conclusion with respect to Factor A is that the p-value is grater than 0.05, there is no significant difference in mean

The p-value of factor B with degree of freedom is (2,24) is (0.01, 0.25)

The conclusion with respect to Factor B is that the p-value is less than 0.05, there is significant difference in mean

The p-value for the interaction of factors A and B with degree of freedom is (6,24) is less than 0.001

The conclusion with respect for the interaction of factors A and Factor B is that the p-value is less than 0.05, there is significant difference in mean

Sourace of variation Sum of squares degree of freedom mean square F Factor A 23 3 23/4=5.75 5.75/2.375=2.42 Factor B 24 2 24/2=12 12/2.375=5.05

Interaction

195 6 195/6=32.5 32.5/2.375=13.68 Error 57 24 57/24=2.375 Total 299 35

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.