The Pulman Mig, Inc. three-station work cel illustrated in the figure below has

Question

The Pulman Mig, Inc. three-station work cel illustrated in the figure below has two machines at station 1 in parallel. (The product needs to go through only one of the two machines belore proceeting to station 2.) 12 minunit Station 1 MachineA Station 2 Station 3 Station 1 Machine B 2 min/nit10 minvun 12 min/unt The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station 3 a) The throughput tme of the new work cell is 24 minutes (enter your response as a whoie number. b) The bottleneck time af the nerw work cell is 12 minutes per unit (oter yoer response as a whole nunber) C) If the frm operates B hours per day, 6 days per week, the weekly capacity of the work cell with the second machine at workstation d) If the firm operates a hours per day, 6 days per week, the weekly capacity of the work cell workstation 3 isunits (enter your response as a whole number) mout the second machine at

Explanation / Answer

In the current setup we have R1a and R1b in parallel, R2 in series and R3 in series, The flow rates at these 3 stations will be C1 = 2*60/12 = 10 units per hour, C2 = 60/2 = 30 units per hour and C3 = 60/10 = 6 units per hour. This means Station 3 is the bottleneck resource.

In new setup, we will have R1a and R2b in parallel, R2 in series ad R3a and R3b in parallel. The flow rates at these 3 stations will be C1 = 2*60/12 = 10 units per hour, C2 = 60/2 = 30 units per hour and C3 = 2*60/10 = 12 units per hour. So, now the bottleneck shifts to Station 1.

a) The throughput time in new workcell is the total time required for processing at Station 1, 2 & 3.

Total Time = T1 + T2 + T3 = 12 + 2 + 10 = 24 mins

The throughput time of the new work cell = 24 minutes

b) The bottleneck in the new setup as mentioned above will be Station 1. Bottleneck time is the time spent by a unit at the bottleneck station 1 which is 12 minutes.

So, Bottleneck time = 12 minutes

c) In the new setup Bottleneck is station 1 and capacity of system will be equal to the capacity of station 1 which is 10 units per hour.

Per day capacity = 8*10 = 80 units/day

Weekly capacity = 6 days * 80 units/day = 480 units per week

d) Without the secod unit at station3, the bottlneck is Station 3 and has a capacity of 6 units per hour.

Per day capacity = 8*6 = 48 units/day

Weekly capacity = 6 days * 48 units/day = 288 units per week

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