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C secure! https//www.mathxlcom/Student/playerHomework.aspx?ho Apps M Ch.6 Watch Transfor ld-461702747&questionld-4;&flushed-false;&icld; Movies-Watch Mov Introduction to OM (Nunnelley Spring 2018 OM 300-003) Homework: HW6 (Chapter 6s) core: 0 of 3 pts roblem 6s.15 The results of inspection of DNA samples taken over the past 10 days are given below Sample size is 100. 7 of 19 (13 complete) Day Defectives 10 2 3 0 a) The upper and lower 3-sigma control chart limits are uCLp-(enter your response as a number between 0 and 1, rounded to three decimal places) Enter your answer in the answer box and then click Check Answer emainingExplanation / Answer
Sum of defectives = 3+5+5+6+3+3+0+4+6+2 = 37
Sample size = n = 100
Total number of samples = number of days x sample size = 10 x100 = 1000
P-bar = Sum of defectives /Total number of samples
= 37/1000
= 0.037
Sp = sqrt of [P-bar(1-P-bar) /n]
= sqrt of [0.037(1-0.037)/100]
= sqrt of 0.00035631
= 0.019
With a three sigma control limit value of Z = 3
UCLp = P-bar + (Z x Sp)
= 0.037 + (3 x 0.019)
= 0.037 + 0.057
= 0.094
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