Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min.
ID: 3479894 • Letter: N
Question
Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml)Explanation / Answer
Alveolar ventilation rate = (tidal volume - total dead space) * respiratory rate
therefore respiratory rate= Alveolar ventilation rate / (tidal volume - dead space)
where total dead space = 200 ml (snorkel volume of 50ml and anatomic dead space of 150 ml)
Also (Tidal volume - dead space) = 500-200 = 300 ml or 0.30 litre
Putting all the values given in the above formula
Respiratory rate = 6 / 0.30
= 20
Respiratory rate = 20 breaths per minute
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