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Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min.

ID: 3479894 • Letter: N

Question

Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Nick’s normally alveolar ventilation rate during mild exercise is 6 liters/min. While at the beach, he goes snorkeling. The snorkel has a volume of 50 ml Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml) Assuming that snorkeling is mild exercise, what would his respiratory rate have to be for him to maintain an alveolar ventilation of 6 listers/min while snorkeling? (Assume a constant tidal volume of 500 ml)

Explanation / Answer

Alveolar ventilation rate = (tidal volume - total dead space) * respiratory rate

therefore respiratory rate= Alveolar ventilation rate / (tidal volume - dead space)

where total dead space = 200 ml (snorkel volume of 50ml and anatomic dead space of 150 ml)

Also (Tidal volume - dead space) = 500-200 = 300 ml or 0.30 litre

Putting all the values given in the above formula

Respiratory rate = 6 / 0.30

= 20

Respiratory rate = 20 breaths per minute

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