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Close Window > Moving to another question will save this response KS Re Question 15 of 21 Question 15 10 points Save Answer What is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? S Activity Crash Time (days) ormal Cost Total Cost with Crashing Immediate Predecessor 300 600 750 $1,200 1,100 400 650 1,650 a, $ 1550 O b.s 3800 ° C. S 2500 O d. $ 3550 Moving to another question will save this response Question 15 of 21 Close Window

Explanation / Answer

First we have to find critical path.

Here activity ABC can be done in parallel. While D must be done after C and E must be done after C.

The critical path is clearly A----D as it will take 12 days. IF we have to crash it by 4 days then the activities need to be done within 8 days.

Now A-- D can be crashed to 8 days. B can be done in 8 days so no point crashing B. While C and E need to be crashed to 8 days.

Hence Activities A, C, D , E need to be crashed fully.

So total cost = 1550.

Activity Normal time Crash time days crashed normal cost total cost with crash cost crash cost crash cost/day immediate predecessor A 6 5 1 800 1100 300 300 - B 8 6 2 300 400 100 Not to crash 50 - C 6 5 1 600 650 50 50 - D 6 3 3 750 1500 750 250 A E 5 3 2 1200 1650 450 225 C

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