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Write a Java application program called Largest.java that inputs a series of 10

ID: 3530934 • Letter: W

Question

Write a Java application program called Largest.java that inputs a series of 10 single-digit numbers and determines and prints the largest of the numbers. Except main() method, no other user-defined method is required. Your program should use at least the following three variables

1. counter: A counter to count to 10 (that is, to keep track of how many numbers have been input and to determine when all 10 numbers have been processed);

2. number: The current digit input to the program; and

3. largest: The largest number found so far.

Belowis what I have so far (I hope that this posts correctly, for some reason I have been having trouble getting it to display right) I need help with an error message for anything input not 0-9, also I kind of want to hide the counter. Any help would be greatly appreciated:

import javax.swing.JOptionPane;


public class Largest
{

// the main method
public static void main(String[] args)
{
int largest = 0;
int counter = 1;
int number = 0;

while ( counter <= 10)
{
number = Integer.parseInt(JOptionPane.showInputDialog("Enter single digit number " +
counter + ": "));
if (number >= 1 && number <= 9)
{
counter++;
if (number > largest)
largest = number;
}
}

JOptionPane.showMessageDialog(null, "The largest number is " + largest);
}

}

Explanation / Answer

please rate


//your code was running fine for integer between 0-9,but you want to hide the counter and also want to calculate the larget that can be anything input not 0-9,then your modified version of code is


import javax.swing.JOptionPane;



public class Largest

{

// the main method

public static void main(String[] args)

{

int largest = 0;

int counter = 1;

int number = 0;


while ( counter <= 10)

{

number = Integer.parseInt(JOptionPane.showInputDialog("Enter single digit number "));


counter++;

if (number > largest)

largest = number;


}


JOptionPane.showMessageDialog(null, "The largest number is " + largest);

}

}

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