Given an integer between 0-999 input by the user, print the English words corres

Question

Given an integer between 0-999 input by the user, print the English words corresponding to that integer.

Similar to previous assignment, your program should print an ending when user choose to end this

program.

Example:

Enter the integer: 1

1 is one

Enter the integer: 11

11 is eleven

Enter the integer: 111

111 is one hundred eleven

Enter the integer: 1111

out of range

Enter the integer: ^D

Thanks for using. This ends the program!

There's two issues with the program below that I got from here (I made some small changes), it doesn't print out the exact values, for example if I try to input 9999 it printouts nine thousand, or if I try to input anything less than 1000 it doesn't print out anything at all. And the second this is I don't know how enter the ^D to end the program.

#include<stdio.h>

#include<math.h>

void print(int n)

{

  int num=n;

  //Declare static strings

  char* lessThan20[] = {

  "zero","one","two","three","four","five","six","seven",

  "eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen",

  "sixteen","seventeen","eighteen","nineteen"

  };

  char* hundred = " hundred ";

  char* thousand = " thousand";

  char* tens[] = { "zero","ten","twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninety"};

  if(num < 0)

  printf(" Its a negative number");

  num = abs(num);

  n = num/ 1000;

  if(n > 0)

  printf(" %s thousand ",lessThan20[n]);

  num=00;

  n = num / 100;

  if(n > 0)

  printf(" %s hundred ",lessThan20[n]);

  num%=100;

  if(num >=20)

  {

  n=num/10;

  if(n>0)

  printf(" %s ",tens[n]);

  }

  else if(num>=10)

  {

  printf(" %s ",lessThan20[num]);

  return;

  }

  num%=10;

  if(num > 0)

  printf(" %s ",lessThan20[num]);

}

int main()

{

  int n;

  printf("Enter a number [Range from 0 - 9999 OR 0 to Exit]: ");

  scanf("%d",&n);

  while(n!= 0)

  {

  printf(" %d is",n);

  //declare member function

  print(n);

  printf(" ");

  //cout <<"Enter a number [ Range 0 - 9999 (or) 0 to exit]: ";

  scanf("%d",&n);

  }

  //pause system

  return 0;

}

Explanation / Answer

Program to Convert Numbers into Words

#include<stdio.h>

void pw(long,char[]);
char *one[]={" "," one"," two"," three"," four"," five"," six"," seven","
eight"," Nine"," ten"," eleven"," twelve"," thirteen"," fourteen","
fifteen"," sixteen"," seventeen"," eighteen"," nineteen"};
char *ten[]={" "," "," twenty"," thirty"," forty"," fifty"," sixty","
seventy"," eighty"," ninety"};


void main()
{
long n;
clrscr();
printf("
Enter any 9 digit no: ");
scanf("%9ld",&n);
if(n<=0)
printf("Enter numbers greater than 0");
else
{
pw((n/10000000),"crore");
pw(((n/100000)0),"lakh");
pw(((n/1000)0),"thousand");
pw(((n/100)),"hundred");
pw((n0)," ");
}
getch();
}


void pw(long n,char ch[])
{
(n>19)?printf("%s %s ",ten[n/10],one[n]):printf("%s ",one[n]);
if(n)printf("%s ",ch);
}

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