Suppose you have a 5Mbps access link (cable or DSL); what is the length of a bit
ID: 3533153 • Letter: S
Question
Suppose you have a 5Mbps access link (cable or DSL); what is the length of a bit on that link? That is, how far does the trailing edge of the bit lag behind the leading edge of the bit on that medium? (Assume the speed of the medium is 2/3 the speed of light).Further, if the DSL line is 3Km, what is the BDP for that link? Pay attention to units and Base 2 Base 10 conversions. wavelength (lamda) = c (speed) / f (cycles/sec)Suppose you have a 5Mbps access link (cable or DSL); what is the length of a bit on that link? That is, how far does the trailing edge of the bit lag behind the leading edge of the bit on that medium? (Assume the speed of the medium is 2/3 the speed of light).Further, if the DSL line is 3Km, what is the BDP for that link? Pay attention to units and Base 2 Base 10 conversions. wavelength (lamda) = c (speed) / f (cycles/sec)
Explanation / Answer
Here Latency = prop * bandwidth prop = 45 microseconds hence Latency = 4.5 * 5 = 22.5 bits (Ans)
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