Consider this function that adds up some elements of an array and then the sampl

Question

Consider this function that adds up some elements of an array and then the sample calls to the right.

cout << sum(a10,10);
cout << sum(a20,10);
cout << sum(a20+10,10);
cout << sum(a10,20);

What pre-condition does this sum function have that is being violated?

Is there any way for this function to verify this pre-condition itself?

  int sum( int *p, int elements )
{
    int total = 0;
    while (elements > 0)
    {
    total += *p;
    elements--;
    p++;
    }
}  

  int a10[10],a20[20];  

cout << sum(a10,10);
cout << sum(a20,10);
cout << sum(a20+10,10);
cout << sum(a10,20);

Explanation / Answer

cout << sum(a20+10,10); this function call will fail as the array when passed as parameter with address seperate , it will have problem analysing this.

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