1.#include int main(){ int a=0; #if (a==0) printf(\"Equal\"); #else if printf(\"

Question

1.#include int main(){ int a=0; #if (a==0) printf("Equal"); #else if printf("Not equal"); #endif return 0; } E (A) Equal (B) Not equal (C) Null (D) Garbage (E) Compilation error 2.What will be output if you will execute following c code? #include int main(){ for(;NULL;) printf("cquestionbank"); return 0; }C (A) c (B) bank (C) cquestionbank (D) Infinite loop (E) Compilation error 3.What will be output if you will execute following c code? #include int main(){ int x=25; if(!!x) printf("%d",!x); else printf("%d",x); return 0; }A (A) 0 (B) 25 (C) 1 (D) -1 (E) 2 4.What will be output if you will execute following c code? #include int main(){ float a=0.5, b=0.9; if(a&&b>0.9) printf("Sachin"); else printf("Rahul"); return 0; }B (A) Sachin (B) Rahul (C) null (D) Run time error (E) Compilation error 5.What will be output if you will execute following c code? C #include int main(){ int x=5, y=10; if(!(!x) && x) printf("%d",x); else printf("%d",y); return 0 ; } (A) 1 (B) 0 (C)5 (D) 10 (E) Compilation error 6.What will be output if you will execute following c code? #include int main(){ char ch=321; printf("%d %c",ch,ch); return 0 ; } B (A) 321 # (B) 65 A (C) 321 ! (D) 66 B (E) Compilation error 7.What will be output if you will execute following c code? #include int main(){ int a,b; a = -3- -3; b = -3 - - (-3 ); printf("%d %d",a,b); return 0 ; }D (A) 0 0 (B) 0 -3 (C) -3 0 (D) 0 -6 (E) Compilation error 8.What will be output if you will execute following c code? #include int main(){ int x; x= -2 + 11 - 7 * 9 % 6 / 12; printf("%d",x); return 0 ; } D (A) 6 (B) 7 (C) 8 (D) 9 (E) Compilation error 9.What will be output if you will execute following c code? #include int main(){ int x=3, y=4, z=4; printf("%d", (z>=y>=x?100:200)); return 0 ; } B (A) 100 (B) 200 (C) 0 (D) 1 (E) Compilation error 10.What will be output if you will execute following c code? #include int main(){ int a=30, b=40, x; x=(a!=10) && (b=50); printf("%d",x); return 0 ; }A (A) 1 (B)2 (C)3 (D) 4 (E) Compilation error

Explanation / Answer

1)

Syntax of conditional preprocessor directive (if) is:



#if <Constant expression>

#else

#endif



In this code (a==0) is not constant expression. A constant expression mean expression doesn%u2019t contain any variables.

Note: const int a; Here a is also variable   

2)

Here NULL is micro constantan. Value of this symbolic constant is 0 or 0L as defined stdio.h:



#ifndef NULL

# if defined(__TINY__) || defined(__SMALL__) || defined(__MEDIUM__)

#      define NULL    0

# else

#      define NULL    0L

# endif

#endif



So corresponding intermediate file of above code will be:





int main(){

    for(;0;)

    printf("cquestionbank");

    return 0;

}



As you know in c :

0: Means false

Non- zero: True



So for loop should not execute any time because intitial condtion is false. But it is bug of turbo c compiler. Loop will execute one time and it will print : cquestionbank


3.

! is negation operator.

!x = 0 if x is non-zero number.

!x = 1 if x is equal to zero.

So,

!!x

=! (! x)

=! (! 25)

=! (0)

=1

As we know in c:

Zero: It represents false.

Non-zero: It represents false.

if (1) means condition is true hence if part will execute.

!x =! 1 = 0

Hence printf statement will print zero in the console window.



4)

Consider on the expression:

a && b > 0.9

As we know > operator enjoy higher precedence than && operator.

So expression will be

a && (b > 0.9)

=0.5 && (0.9 > 0.9)

Properties of > (Greater than operator)

a > b returns 1 if a is greater than b.

a > b return 0 if a is less than or equal to b.

So our expression became:

= 0.5 && 0

In c zero represents false and non-zero represents true.

= true && false

= false

= 0

So, if (0) means condition is false. Hence else part will execute.



5)

Consider on expression:

! (! x) && x

=! (! 5) && 5

=! 0 && 5

=1 && 5

=1

So, if condition is true.



6)

Number 321 is beyond the range of char variable ch. So ch will store corresponding cyclic value as




Equivalent cyclic value of 321 = 321 % 128 = 65

65 is ASCII value of character 'A'



7)

Operator in c has two forms:

- : Unary minus operator (It requires one operand)

- : Binary minus operator (It requires two operands)

Note: Unary minus operator has higher precedence than binary minus operator.

8)

Consider on the expression

x = -2 + 11 - 7 * 9 % 6 / 12

There are seven different type of operator in the above expression:



Operator
  

Precedence
  

Associative

-
  

1
  

Right to left

* , % , /
  

2
  

Left to right

- , +
  

3
  

Left to right

=
  

4
  

Right to left


First of all unary minus will perform the operation

x = (-2) + 11 - 7 * 9 % 6 / 12

Now multiplication operator will perform the operation

x = (-2) + 11 - (7 * 9) % 6 / 12

x = (-2) + 11 - 63 % 6 / 12

After this modular division operator will perform operation:

x = (-2) + 11 - (63 % 6) / 12

x = (-2) + 11 - 3 / 12

After this division will perform the operation:

x = (-2) + 11 - (3 / 12)

x = (-2) + 11 - 0

Now binary plus operator will perform the operation:

x = ((-2) + 11) - 0

x = 9 - 0

Now binary minus operator will perform the operation:

x = 9

At the end assignment operator will perform the operation and it will assign 9 to variable x.

9)

Consider on arithmetical expression:

z>=y>=x? 100:200

= (z >= y >= x? 100: 200)

= (4 >= 4 >= 3? 100: 200)

= ((4 >= 4) >= 3? 100: 200)

= (1 >= 3? 100: 200)

= (0? 100: 200)

= 200

10)

(a!= 10) && (b = 50)

= (30! = 10) && (50)

= 1 && 50

= 1

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