1) Assume that x is a char variable has been declared and already given a value

Question

1) Assume that x is a char variable has been declared and already given a value . Write an expression whose value is true if and only if x is alphanumeric , that is either a letter or a decimal digit.

2) Assume that x is a char variable has been declared and already given a value . Write an expression whose value is true if and only if x is NOT a letter.

3) Assume that x is a char variable has been declared and already given a value . Write an expression whose value is true if and only if x is a letter.

4)

Explanation / Answer

//

// main.cpp

// Chegg

//

// Created by Satya Prakash on 02/07/13.

// Copyright (c) 2013 Satya Prakash. All rights reserved.

//

#include <iostream>

#include <math.h>

#include <cmath>

using namespace std;

int main(int argc, const char * argv[])

{

char var;

bool exp1,exp2,exp3;

cout<<"Enter an character "<<endl;

cin>>var;

if ((48 <=var && var<=57) || (var>=65 && var<=90) || (var>=97 && var<=122)) {

exp1=true;

cout <<"inpur character is alphanumaric "<<endl;

}

if (!((var>=65 && var<=90) || (var>=97 && var<=122))) {

exp2=true;

cout <<"inpur character is not a letter "<<endl;

}

if (((var>=65 && var<=90) || (var>=97 && var<=122))) {

exp3=true;

cout <<"inpur character is a letter "<<endl;

}

// exp1 =((48 <=var && var<=57) || (var>=65 && var<=90) || (var>=97 && var<=122))

// exp2 =(!((var>=65 && var<=90) || (var>=97 && var<=122)))

// exp3 = (((var>=65 && var<=90) || (var>=97 && var<=122)))

return 0;

}

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