Create a linked list structure Music that contains the data fields Name, Artist,

Question

Create a linked list structure Music that contains the data fields Name, Artist, Number_of_Songs, and a pointer to the list. Create the structure with 3 members and fill in data for each member. Create a function that will display() all the data for each member and call it from the main program.
I saw the other answer to this but it is not compiling, i get

1>------ Build started: Project: final2, Configuration: Debug Win32 ------
1>  stdafx.cpp
1>  AssemblyInfo.cpp
1>  final2.cpp
1>final2.cpp(30): error C2440: '=' : cannot convert from 'item *' to 'list *'
1>          Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
1>final2.cpp(39): error C2440: '=' : cannot convert from 'list *' to 'item *'
1>          Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
1>  Generating Code...
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

Explanation / Answer

please rate - thanks

your code corrected

I think you should you gets for the name so you can have a space-but didn't change it since wasn't sure

#include <conio.h>
struct Music {
char artist[30];
int no_of_songs;
struct Music *next;
};

typedef struct Music item;

int main() {
//item * curr, * head;
struct Music *head, *curr;
int i;
char arti[30];
int k;
head = NULL;

for(i=1;i<4;i++) {
    curr = (item *)malloc(sizeof(item));
    printf(" Enter Artsit name ");
    scanf("%s",arti);
    strcpy(curr->artist,arti);
    printf(" Enter no of Songs ");
    scanf("%d",&k);
    curr->no_of_songs = k;
    curr->next = head;
    head = curr;
   }
curr = head;

while(curr)
{
printf("Artist Name: %s No of songs :%d ",curr->artist,curr->no_of_songs);
curr = curr->next ;
}
getch();
return 0;
}

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