Modify the given code such that negative inputs do not break the program and the

Question

Modify the given code such that negative inputs do not break the program and the smallest number that broke the program before now works. Do not hardcode answers.

#include <iostream>
#include <cstdlib>

using namespace std;

/*
* Will compute and return the factorial value of the given number.
* Remember factorial is the product of all positive integers less
* than or equal to the given number.
*
* e.g 4! = 4 * 3 * 2 * 1 = 24
*/
int factorial(short number);

int main() {
  short number;
  cout << "Enter a number: ";
  cin >> number;

  cout << "The factorial of " << number << " is ";
  cout << factorial(number) << endl;

  exit(EXIT_SUCCESS);
}

/*
* Will compute and return the factorial value of the given number.
* Remember factorial is the product of all positive integers less
* than or equal to the given number.
*
* e.g 4! = 4 * 3 * 2 * 1 = 24
*/
int factorial(short number) {
  //start our accumulator at 1 since 0! == 1
  int accumulator = 1;

  //until we reach 0
  while (number > 0) {
    //multiple our product by the current number
    accumulator = accumulator * number;
    //then decrement to the next lowest value
    number = number-1;
  }

  return accumulator;
}

Explanation / Answer

#include <iostream>

#include <cstdlib>

using namespace std;

int factorial(short number);

int main()

{

short number;

cout << "Enter a number: ";

cin >> number;

cout << "The factorial of " << number << " is ";

cout << factorial(number) << endl;

exit(EXIT_SUCCESS);

}

int factorial(short number)

{

if(number<0)

{

return -1;

}

int accumulator = 1;

while (number > 0) {

accumulator = accumulator * number;

number = number-1;

}

return accumulator;

}

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