Create a program that determine if a number is divisible by 2, 3 and 5. BEWARE:

Question

Create a program that determine if a number is divisible by 2, 3 and 5. BEWARE: a number is divisible by the other only when the remaining residue is 0

Example 1:

Enter a number: 10

cout<< 10 is divisible by 2

cout<< 10 [ IS NOT ] is divisible by 3

cout<< 10 is divisible by 5

Example 2:

Enter a number: 15

cout<<15 [ IS NO T] divisible by 2

cout<<15 is divisible by 3

cout<<15 is divisible by 5

Example 3:

Enter a number: 7

cout<< 7 [ IS NO T] divisible by 2

cout<< 7 [ IS NO T] divisible by 3

cout<< 7 [ IS NO T] divisible by 5

Explanation / Answer

please rate - thanks

any changes needed, I'll make them

I assumed no functions

#include <iostream>
using namespace std;
int main()
{int n;
cout<<"Enter a number: ";
cin>>n;
if(n%2==0)
    cout<<n<<" is divisible by 2 ";
else
    cout<<n<<" is [IS NOT] divisible by 2 ";
if(n%3==0)
    cout<<n<<" is divisible by 2 ";
else
    cout<<n<<" is [IS NOT] divisible by 2 ";
if(n%5==0)
    cout<<n<<" is divisible by 5 ";
else
    cout<<n<<" is [IS NOT] divisible by 5 ";
    system("pause");
    return 0;
}     

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