Jot down a false answer and expect points. No scams leading off site for private

Question

Jot down a false answer and expect points. No scams leading off site for private tutor help. Any scammed answeres. will be reported to                    customer service, flagged, and given 1 star.

                    5. Beginning with one start bit followed by 21 data bits, 2 parity bits and 1 stop bit:                 

                        a) What are the total number of bits in the frame?                     

                        b) What would the overhead and throughput be (answer in percent)?                     

                        c) How many ASCII characters could be carried in this frame?                     

                        d) What data rate would you need in order to deliver 9,600 ASCII characters per second to the destination?

                    6. A transmitter sends 100 bits per second but the receiver's clock runs too slowly causing it to measure once every 0.0107 seconds. How many bits are measured                    in a row before the receiver misses a bit?

                        [Hint: After measuring the first bit, measurements get later and later with each incoming bit. Eventually, the measurement drifts more than half a bit time                        and lands in the following bit. Assume the first bit is measured exactly in the center of the bit time.]

Explanation / Answer

A transmitter sends 100 bits per second but the receiver's clock runs too slowly causing it to measure once every 0.0107 seconds. How many bits are measured in a row before the receiver misses a bit?

[Hint: After measuring the first bit, measurements get later and later with each incoming bit. Eventually, the measurement drifts more than half a bit time and lands in the following bit. Assume the first bit is measured exactly in the center of the bit time.]

e . It will miss a bit if reciever lands after that bit i.e. instead of falling in middle it drifts every time and its so happens every time it drifts a bit and some time it lands out of the bit to be measured so it misses this bit .

transmitter sends 100 bits per second so one bit per every 1/100 seconds = 0.01

so reciever will recieve every bit for every 0.01 seconds .

and its given reciever measured exactly in the center of the bit time .

so due to drifting we must drift that amount so that it misses one of them i.e. it should drift by > 0.0107/2 then its going to miss this bit ,

Here drifting for every bit is 0.0007 secs , (transmitter rate - reciever rate)

lets assume it happens after f number of bits so, f * 0.0007 = 0.0107 /2 => f = 15.28571429

f = f = 15.28571429 bits

Related Questions

Navigate

• Browse (All)
• Browse J
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.