Write a program that reads in a set of positive integers and outputs how many ti

Question

Write a program that reads in a set of positive integers and outputs how many times a particular number appears in the list. Assume that the data set has at most 100 numbers and -999 marks the end of the input data. The numbers must be output in increasing order. For example, for the data

15 40 28 62 95 15 28 13 62 65 48 95 65 62 65 95 95 -999

the output is

Number                        Count

13                                 1

15                                 2

28                                 2

40                                 1

48                                 1

62                                 3

65                                 3

95                                 4

Explanation / Answer

#include "iostream"

using namespace std;

int main()

{

const int array_size = 100;

int array[array_size];

int i = 0;

int number;

int c;

for(int c = 0;c < array_size; c++)

{

array[c] = 0;

}

cout << "Enter the sequence of digits: " ;

while((cin >> number) && (number >= 0) &&(number!=-999))

{

if(number >=array_size)

{

cout << "Input: " << number << " is out ofrange. ";

continue;

}

array[number]++;

i++;

}

cout << "The digit frequency counts: " << " ";

for(c=0;c < array_size; c++)

{if(array[c]!=0)

cout << " Digit " << c<< " has frequency " << array[c] <<" ";

}

system ("PAUSE");

return 0;

}

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