1. Perform the following addition on unsigned integers assuming a nine-bit cell.

Question

1. Perform the following addition on unsigned integers assuming a nine-bit cell. Show the effect on the carry bit:

        111111111

add  111111111

c=   ___________

2.Perform the following addition, assuming nine-bit two's complement binary representation. Show the effect on the status bits:

           100011011

    add 101010100

NZVC=  _________

3.Perform the following logical operation, assuming a nine-bit cell:

XOR 010010011

         101110101
NZ=_____________

4. Assuming nine-bit two's complement representation, convert the following number to binary, show the effect of the ASL operation on it, and the convert the result back to decimal:

-62 (dec) = ______ (bin)
After applying the ASL operation: ________ , NZVC = __________
Converting back to decimal gives:  ________ (dec)

The effect of the ASL is to__________ the number

5.Assuming a nine-bit cell, show the effect of the rotate operation on each of   the following values with the given initial value of C:

C = 1, ROL 0 0110 1101 = __ _ _ _ _ _ _ _ _ c=_

C = 1, ROR 0 0110 1101 =_ _ _ _ _ _ _ _ _ c=_

(use 1s or 0s)

6. Assuming nine-bit two's complement binary representation, convert the following number from hexadecimal to binary to decimal:

0F5 (hex) = ____   (bin)
                 = ___ (dec)

7. Assuming nine-bit two's complement binary representation, write the bit pattern for the following decimal number in binary and hexadecimal:

-73 (dec) = _______ (bin)
                = _____ (hex)

Explanation / Answer

(1)

Carry = 1 1 1 1 1 1 1 1 1

A = 1 0 0 0 1 1 0 1 1

B = 1 1 1 1 1 1 1 1 1

______________________

A+B = 1 1 1 1 1 1 1 1 1 0

______________________

But it is of 9 bits. So, the leftmost bit is not considered.

That is c = 1 1 1 1 1 1 1 1 0 where each of A and B are equal to

1 1 1 1 1 1 1 1 1 and 1 1 1 1 1 1 1 1 1 respectively.

(2)

Carry= 1 1 1 1 1 1 1 0 0

A = 1 1 1 1 1 1 1 1 1

B = 1 0 1 0 1 0 1 0 0

______________________

A+B = 1 1 0 1 0 1 0 0 1 1

______________________

As it is of 9 bits again then write in the form of

So NZVC = 101010011.

(3)

XOR of

A = 0 1 0 0 1 0 0 1 1

B = 1 0 1 1 1 0 1 0 1

______________________

A^B = 1 1 1 1 0 0 1 1 0

______________________

NZ = 111100110.

(4)

(-62) dec = 1's complement (62-1) = (1 1 1 0 0 0 0 1 0) bin

(5)

In the first case, C = 1 and the operand is 0 0110 1101 .

changes to 0.

In the second case, C = 0 and the operand is 0 0110 1101.

·         When ROR is executed on the same operand, the operand shifts to right by one bit and the carry will equal to the newly formed MSB.

·         From the above case, the operand becomes 1 0011 0110 and the carry changes to 1.

(6)

0F5 (hex)   hexadecimal into decimal format   245 (dec)

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