Create a pseudocode using if instruction containing a compound condition that wi
ID: 3544918 • Letter: C
Question
Create a pseudocode using if instruction containing a compound condition that will satisfy the following: When employeeCode is equal to MGR and SALARY is greater than 100,000, display "This manager is eligible for a five percent bonus for the year." Otherwise, when employeeCode is equal to MGR and SALARY is greater than 250,000, display "This manager is eligible for a 10 percent bonus for the year." In all other cases, display "This person is not eligible for a bonus for the year."
Note: The above text is not in a pseudocode format. You need to use the IF ELSE ENDIF clause in a pseudocode format with appropriate relational and logical operators
PSEUDOCODE ONLY
Explanation / Answer
pseudocode
Start
IF employeeCode == MGR && SALARY > 100000 && SALARY < 250000
print "This manager is eligible for a five percent bonus for the year."
ELSE IF employeeCode == MGR && SALARY > 250000
print "This manager is eligible for a 10 percent bonus for the year."
ELSE
Print "This person is not eligible for a bonus for the year."
ENDIF
END
Explanation
Trick was the section when salary is > 250000
and salary is > 100000.
Here I have used two conditions for salary in first if statement just to check for the range when salary is > 100000 but lesser than 250000.
Second condition will check for salary greater than 250000
anything else is handled by ELSE block
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