Create a function that prints an array of ints using pointer arithmetic. Assume

ID: 3545402 • Letter: C

Question

Create a function that prints an array of ints using pointer arithmetic. Assume that the caller will give you valid addresses (i.e. they are actually the starting and ending points of the array) and that you do not have to handle empty arrays.
- Parameters:
  - pStart (int pointer) = A pointer to the start of the array
  - pEnd (int pointer) = A pointer to the end of the array (i.e. the last element in the array)
- Returns:
  - Nothing
Make another function that does the exact same thing, but with strings (i.e. char pointers) instead of ints.
Test the functions by printing the following arrays (copy and paste these into your main function, they should make the arrays for you):
- int iArray[] = {12, -2, 4, 123, 9, 0};
- int iArray2[] = {1};
- char *strArray[] = {"Hi", "I hope", "this exercise", "was", "easy", "!"};
- char *strArray[] = {""};

void public printInt(*pStart,*pEnd){

for(pStart;pStart<=pEnd;pStart++)

{

prinf("%d",*pStart);

}

void public printChar(*pStart,*pEnd){

for(pStart;pStart<=pEnd;pStart++)

{

prinf("%c",*pStart);

}

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