1. The following function uses reference variables as parameters. Rewrite the fu

Question

1.

The following function uses reference variables as parameters. Rewrite the function so it uses pointers instead of reference variables, and then demonstrate the function in a complete program.

int dosomething(int &x, int &y)
{
int temp =x;
x = y * 10;
y = temp * 10;
return x + y;
}

2.

Write a function that accepts an int array and the array and the arrays size as arguments. The function should create a new array that is one element larger than the argument array. The first element of the new array should be set to 0. Element 0 of the argument array should be copied to element 1 of the new array, element 1 of the argument array should be copied to element 2 of the new array, and so forth. The function should return a pointer to the new array.

Explanation / Answer

2.

#include<stdlib.h>
#include<iostream.h>
#include<string.h>
char *a(char *,int);
int main(char *argv[],int argc)
{
int x,n,i=0,t,num=0;
FILE *fd;



char *grid;
char *y;
grid = (char *)malloc(sizeof(char) * 9 * 9);
y=(char *)malloc(sizeof(char) * 9 * 9);
cout<<"enter value";
cin>>x;
if(x<50)
{
n=x;

if (argv[1] != NULL){
fd = fopen(argv[1], "r");
while (num!= n)
{
fscanf(fd, "%c",grid[i]);
num++;
i++;
}

}

y[n+1]=a(grid,n);
for(i=0;i<n;i++)
cout<y[i]<<endln;
return(0);
}
else if(x>50)
return 0;
}
char *a(char *grid[],int n)
{
char x[n+1];
int i;
x[0]=0;
for(i=0;i<n;i++)
x[i+1]=grid[i];

return x;
}   

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.