Problem#2 ( True or False ) (1) Any binary search tree can be brought into AVL b

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Problem#2 ( True or False )
(1) Any binary search tree can be brought into AVL balance by performing a sequence of rotations. (2) Given an array of n numbers (keys) in sorted order, an AVL tree on those keys can be built in time O(n). (3) Inserting into an AVL tree with n nodes requires O (log n) rotations. (4) Even though BFS and DFS have the same space complexity, they do not always have the same worst case asymptotic time complexity. (5) A DFS forest is defined as the collection of all the trees generated when DFS is run on a graph. Then,
true or false: Any DFS forest of an undirected graph contains the same number of trees. (6) Given a graph G = (V, E) with positive edge weights, the Bellman-Ford algorithm and Dijkstra Problem#2 ( True or False )
(1) Any binary search tree can be brought into AVL balance by performing a sequence of rotations. (2) Given an array of n numbers (keys) in sorted order, an AVL tree on those keys can be built in time O(n). (3) Inserting into an AVL tree with n nodes requires O (log n) rotations. (4) Even though BFS and DFS have the same space complexity, they do not always have the same worst case asymptotic time complexity. (5) A DFS forest is defined as the collection of all the trees generated when DFS is run on a graph. Then,
true or false: Any DFS forest of an undirected graph contains the same number of trees. (6) Given a graph G = (V, E) with positive edge weights, the Bellman-Ford algorithm and Dijkstra

Explanation / Answer

1. True. Using Left or right rotation

2. False

3. True

4. Depends upon data which is searched and wheere it is found

5. True

6. Flase

7. False

8. True

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