load these values into Matlab create an appropriately annotated graph of positio
ID: 3548442 • Letter: L
Question
load these values into Matlab create an appropriately annotated graph of position vs time points. Plot the data points AND best fit curves for both objects in different colors on the same graph. The graph that you create will be worth 10 points. (We will not actually grade your files for the practice exam. We WILL for the REAL exam!) Note: Since acceleration is constant, its graph is a horizontal line. Since acceleration is the second derivative of position, what order should your position polynomial be? Based on a best-fit polynomial for A's position, determine an approximate value for the velocity of object A at 4.5 seconds, (m/s) Based on a best-fit polynomial for B's position, calculate B's acceleration, (m/s2)Explanation / Answer
clear all
clc
t=(0:0.5:7.5)'; % time as given in table
Pos_A=[0 0.14 0.53 1.08 2.18 3.03 4.36 5.75 8.81 10.02 12.37 16.35 20.01 22.84 24.99 29.26]'
fit_Pos_A=fit(t,Pos_A,'poly2') % Position A curve fit
Pos_B=[0 0.22 0.95 2.19 3.79 5.43 7.81 11.84 13.17 17.22 21.26 28.97 30.29 39.33 48.24 45.81]';
fit_Pos_B=fit(t,Pos_B,'poly2')% Position V curve fit
Vel_A=diff(Pos_A) % Velocity
t1=(0.5:0.5:7.5)'; % Time for velocity
fit_Vel_A=fit(t1,Vel_A,'poly1')% Velocity A curve fit of linear type
Vel_B=diff(Pos_B)
fit_Vel_B=fit(t1,Vel_B,'poly1')% Velocity B curve fit of linear type
%Plots
figure(1)
plot(fit_Pos_A,t,Pos_A)
figure(2)
plot(fit_Pos_B,t,Pos_B)
% Interpolated Values
Vel_A_45=fit_Vel_A(4.5)
Accl_B=fit_Vel_B(1)-fit_Vel_B(0) % y=mx+c p we have to find m to get the accelaration so we %first put x=1 and then x=0 to get the m
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