Write a C++ function int rectArea (int l en, int wid) that returns the area of a

Question

Write a C++ function

int rectArea (int l en, int wid)

that returns the area of a rectangle with length l en and width wid. Test it with a main

program that inputs the length and width of a rectangle and outputs its area. Output the

value in the main program, not in the function.

Sample Input

6  10

Sample Output

The area of a 6 by 10 rectangl e is 60.

Part 2-----------

Write a recursive void function called rotateLeft that rotates the first n integers in

an array to the left. To rotate n items left, rotate the first n

Explanation / Answer

program 1

#include<iostream>
using namespace std;
int rectArea(int len,int wid);
int main()
{
int l,w,a;
cout<<"Enter the length and width of the rectangle ";
cin>>l>>w;
a = rectArea(l,w);
cout<<"The area of a "<<l<<" by "<<w<<" rectangle is "<<a<<endl;
system("pause");
}

int rectArea(int len,int wid)
{
int a;
a= len*wid;
return a;
}

program 2

#include<iostream>
using namespace std;
void rotateLeft(int *a,int m,int c);
int main()
{
    int n;
    cout<<"Enter the size of the array ";
    cin>>n;
    int a[n];
    cout<<"Enter the elements of the array ";
    for(int i=0;i<n;i++)
    cin>>a[i];
    cout<<"The elements of the array in order are ";
    for(int i=0;i<n;i++)
    cout<<a[i]<<" ";
    cout<<" Upto which array index do you want the array to be rotated? ";
    int m;
    cin>>m;
    rotateLeft(a,m,m);
    cout<<"After rotation the elements of the array are ";
    for(int i=0;i<n;i++)
    cout<<a[i]<<" ";
    cout<<endl;
    system("pause");
    }
   
void rotateLeft(int *a,int m,int c)
{
     int k,l,n;
     n=c;
     if(m < 2)
          return;
     else{
     k = a[m-2];
     a[m-2] = a[m-1];
     a[m-1] = k;
       rotateLeft(a,m-1,c);
     }
     }

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