Write a program to convert from decimal to Hexadecimal. Cannot use Integer.toHex
ID: 3550588 • Letter: W
Question
Write a program to convert from decimal to Hexadecimal. Cannot use Integer.toHexString(in). Program also has to check if decimal entered is possitive.This is what I have so far. Cannot figure out what I am doing wrong. When I enter 25 result comes out as 1 which is not wright.
import java.lang.*;
import java.util.Scanner;
public class FindHexString {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String hex = "";
int decimal = 0;
int remainder = 0;
int quotient = 0;
System.out.print("Enter a number to be converted: ");
decimal = input.nextInt();
while (decimal > 16) {
quotient = decimal / 16;
remainder = decimal % 16;
do {
remainder = decimal % 16;
if (remainder == 10) {
hex = "A" + hex;
}
if (remainder == 11) {
hex = "B" + hex;
}
if (remainder == 12) {
hex = "C" + hex;
}
if (remainder == 13) {
hex = "D" + hex;
}
if (remainder == 14) {
hex = "E" + hex;
} else if (remainder == 15) {
hex = "F" + hex;
}
} while (decimal < 16);
decimal--;
}
System.out.print("Your number in hexadecimal is: " + hex + quotient);
}
}
Explanation / Answer
public class DecToHex {
public static void main(String[] args) {
System.out.println(decToHex(25));
}
public static String decToHex(int in){
String digits = "0123456789ABCDEF";
String result = "";
while(in>0){
result = digits.charAt(in%16) + result;
in /= 16;
}
return result;
}
}
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