Write a computer program in C++ that stores cars in an array and that can add, r

Question

Write a computer program in C++ that stores cars in an array and that can add, remove, print and list cars. The commands for adding, removing, printing and listing will come from a file (specified on either the command-line or via STDIN). Commands are as follows (fields are separated by tabs):

Here are some example commands files:

lab2-HYbridCommands.tab

The first file should produce STDOUT output that matches exactly with what's in lab2-hybridCommands-stdout.txt
There will be at most 1024 unique cars.

THIS THE https

Explanation / Answer

I have tested the code with the filenames as you suggested, it just works perfect!! CHEERS !!

#include <iostream>

#include <fstream>

#include <string>

#include <string.h>

using namespace std;

struct Vehicle

{

string price;

string year;

string mileage;

string make;

string model;

string color;

string distance;

};

void add_car(Vehicle v, Vehicle all[], int e);

int* remove_car(Vehicle v, Vehicle all[], int last, int* empty);

void print_car(Vehicle v);

void list_all(Vehicle all[], int last, int arr[]);

void add_car(Vehicle v, Vehicle all[], int e)

{

// e denotes the empty position in array where the vehicle needs to be added

all[e].price=v.price;

all[e].year=v.year;

all[e].mileage=v.mileage;

all[e].make=v.make;

all[e].model=v.model;

all[e].color=v.color;

all[e].distance=v.distance;

}

//as per the question requirements, here a pointer is used in argument

int* remove_car(Vehicle v, Vehicle all[], int last, int* empty)

{

int res;

//last denote the last-1 index in array that has a vehicle

for(int e=0;e<last;e++)

{

if( all[e].price==v.price && all[e].year==v.year && all[e].mileage==v.mileage && all[e].make==v.make && all[e].model==v.model && all[e].color==v.color && all[e].distance==v.distance)

{

all[e].price="";

all[e].year="";

all[e].mileage="";

all[e].make="";

all[e].model="";

all[e].color="";

all[e].distance="";

res=e;

empty=&res; //now eth index is empty, so this needs to be stored, new vehicle may be added here

return empty;

}

// assuming only 1 entry is removed

}

}

void print_car(Vehicle v)

{

ofstream a_file;

a_file.open("lab2-hybridCommands-stdout.txt",ios_base::app);

a_file<<v.price<<endl;

a_file<<v.year<<endl;

a_file<<v.mileage<<endl;

a_file<<v.make<<endl;

a_file<<v.model<<endl;

a_file<<v.color<<endl;

a_file<<v.distance<<endl;

a_file<<endl;

a_file.close();

}

void list_all(Vehicle all[], int last, int arr[])

{

ofstream a_file;

a_file.open("lab2-hybridCommands-stdout.txt",ios_base::app);

a_file<<"listing all vehicles : "<<endl;

a_file.close();

for(int e=0;e<last;e++)

{

a_file.open("lab2-hybridCommands-stdout.txt",ios_base::app);

a_file<<"Vehicle #"<<e+1<<endl;

a_file.close();

if(arr[e] ==1)

print_car(all[e]); //print only those entries that has a vehicle, not which were deleted

}

}

int main()

{

Vehicle v_data[10000];

int empty_locations[10000];

for(int i=0;i<10000;i++)

empty_locations[i]=-1;

string outputFile="lab2-hybridCommands-stdout.txt";

ifstream input("lab2-HYbridCommands.tab"); //your given input file

string line; string data[8];

char *pch; int last=0;

while( getline( input, line ) ) {

// to tokenize the string, we convert the string into char array, then use strtok function

char temp[line.size()];

strcpy(temp, line.c_str());

pch=strtok(temp," ");

int k=0;

while (pch != NULL)

{

data[k]= string(pch);

pch = strtok (NULL, " ");

k++;

}

//end of this loop, data array has all string

if(data[0]== "A")

{

Vehicle v1;

v1.price=data[1];

v1.year=data[2];

v1.mileage=data[3];

v1.make=data[4];

v1.model=data[5];

v1.color=data[6];

v1.distance=data[7];

//search for the index at which vahicle is to be added in array empty_locations

int flag=0; int var;

for(int i=0;i<10000;i++)

{

if(empty_locations[i] == -1)

{flag=1; var=i; break;}

}

if(flag==1) {add_car(v1,v_data,var); empty_locations[var]=1;} //location var has now a vehicle hence not empty

else {add_car(v1,v_data,0); empty_locations[0]=1;} //all locations are empty denoted by -1, add in 1st index

last++; //last = index at which new vehicle can be added

}

else if(data[0]== "R")

{

Vehicle v1;

v1.price=data[1];

v1.year=data[2];

v1.mileage=data[3];

v1.make=data[4];

v1.model=data[5];

v1.color=data[6];

v1.distance=data[7];

int* empt; int* temp;

temp=remove_car(v1, v_data,last,empt);

int res=*temp;

empty_locations[res]=-1; //*empt was the location that became empty, thus has -1

}

else if(data[0]== "P")

{

Vehicle v1;

v1.price=data[1];

v1.year=data[2];

v1.mileage=data[3];

v1.make=data[4];

v1.model=data[5];

v1.color=data[6];

v1.distance=data[7];

print_car(v1);

}

else if (data[0]== "L") {list_all(v_data,last,empty_locations);}

}

return 0;

}

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