Consider the program below which does some simple aritmetic operations and print

Question

Consider the program below which does some simple aritmetic operations and prints the results. Fill in the missing statements and trace the output.

#include "iostream"

int main ()

{

     // Declare 4 integer variables, w, x, y, and z, with initial

     // Values of 5, 4, 8 and 2 respectively.

    //********your code goes here

    int result;

    // What value will be stored in result after each of the

    // following statements are executed? write your answer at

    // the comment line on the right of each statement.

    result = x + y % w / z;           // result is______

    result = y / x * 2;                 // result is______

    result = (y - z) / (z % w);      // result is_______

    cout << result << endl;          // _______will be printed

     system("pause");

     return 0;

}

Detailed computation (including the memory drawing) for

   result = x + y % w / z

Detailed computation (including the memory drawing) for

result = y / x * 2;

Detailed computation (including the memory drawing) for

result = (y - z) / (z % w)

Explanation / Answer

In general a compiler uses infix to postfix conversion and then computes any expression.

in theis program the missing statements are :

int w = 5,x = 4,y = 8,z = 2;

result = x + y % w / z;           // result is______ 5

1st : y % w = 8 % 5 = 3(quotient)

2nd 3 / z = 3 / 2 = 1(integer)

3rd : x + 1 = 5

result is modified to store 5

    result = y / x * 2;                 // result is______ 1

the computation is started from right always

1st : X * 2 = 8

2nd : y / 8 = 1

result is modified to store 1

    result = (y - z) / (z % w);      // result is_______ 3

1st : z % w = 2 % 5 = 2

2nd : y - z = 8 - 2 = 6

3rd : 6 / 2 = 3

result is modified to store 5

    cout << result << endl;          // _______will be printed 3

since the last value stored in result is 3

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