I am writing a C++ program which opens a data file and then displays its content

Question

I am writing a C++ program which opens a data file and then displays its contents with line numbers. That is the program should display the number 1 and then the first line of the file, then the number 2 and the second line of the file, etc. I am able to open and display the file, but now I want to be able to just display a specific line using a printline() function. Any help would be greatly appreciated. Here's the code that I have written so far:

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main ()

{

string filename1;

ifstream qFile1;

string qLine1;

cout<<"Please enter your file name (robotics.txt): "<<endl;

cin>>filename1;

qFile1.open(filename1.c_str());

if (!qFile1.good())

{

cout<<"Could not open file"<<endl;

return 1;

}

while (!qFile1.eof())

{

getline(qFile1, qLine1);

cout<<qLine1<<endl;

}

qFile1.close();

return 0;

}

Explanation / Answer

void printline(int linenumber)

{

string qLine1;

for(int i=0;i<linenumber;i++)

{

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