Describe the output of the following program and explain why it is produced. pub

Question

Describe the output of the following program and explain why it is produced.

public class Main {
   public static void main (String[] args) {
       Base b = new Derived ();
       b.foo();
   }
}
class Base {
   public static void foo() { System.out.println("Base"); }
}
class Derived extends Base {
   public void foo() { System.out.println("Derived"); }
}

Describe the output of the following program and explain why it is produced.

struct base {
   virtual void foo(void) { cout << "base" << endl; }
}
struct derived : base {
   void foo(void) { cout << "derived" << endl; }
}
int main(void) {
   base *b = new derived;
   b -> foo();
   return 0;
}

Explanation / Answer

case 1

compilation error will occur because in base class foo is static and cannot be overidden in derived class

but if it is not static then output "Derived" will be produced because and object of base b will see than foo is overidden in the derived class and thus it will invoke the method of derived class

case 2

"derived" will be produced as output because and object of base struct b will see than foo is overidden in the derived struct and thus it will invoke the functor of derived class

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