The following code should convert a decimal to hexadecimal in Java: System.out.p

Question

The following code should convert a decimal to hexadecimal in Java:

System.out.println("The decimal number you enter will be converted to its hexadecimal equivalent.");

       System.out.println("Please enter a decimal number: ");

       Scanner keyboard = new Scanner(System.in);

       int dec = keyboard.nextInt();

       int input = dec;

       String hex = "";

       char dig[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
      
       while(dec > 0)
       {
           input = dec%16;
          
           hex = dig[input] + hex;
          
           dec = dec / 16;
       }

       System.out.println("The decimal number you entered, " + input + " is " + hex + " in hexadecimal. ");

}

The conversion works fine, where you see input in System.out.println("The decimal number you entered, " + input + " is " + hex + " in hexadecimal. "); shows the wrong value and I think it is because it is modified during the coding process. Any idea how to fix this? Thanks.

Explanation / Answer

Try this

import java.io.*;

class Dec2Hex

{

    public static void main(String args[])throws IOException

    {

        BufferedReader br=new BufferedReader (new InputStreamReader(System.in));

        System.out.print("Enter a decimal number : ");

        int n=Integer.parseInt(br.readLine());

        int r;

        String s=""; //variable for storing the result

        //array storing the digits (as characters) in a hexadecimal number system

        char dig[]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};

        while(n>0)

            {

                r=n%16; //finding remainder by dividing the number by 16

                s=dig[r]+s; //adding the remainder to the result

                n=n/16;

            }

        System.out.println("Output = "+s);

    }

}

THis code is working fine on my pc..

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